Answer:
Explanation:
Equivalent resistance
Re = 100 + (1/( 1/270 + 1/(150 + 240)))
Re = 100 + (1/( 1/270 + 1/390))
Re = 100 + 159.5
Re = 259.5 Ω
Power drawn from battery = V²/R
P = 12²/259.5
P = 0.554816...
P = 0.55 W
circuit current
I = V/Re
I = 12 / 259.5
I = 0.04623...A
I = 46 mA
100 Ω resistor
V = IR = 0.04623(100) = 4.6 V
I = 46 mA
P = VA = 4.6(0.046) = 0.21376...
P = 0.21 W
270 Ω resistor
V = 12 - 4.6 = 7.4 V
I = V/R = 7.4/270 = 0.02732... = 27 mA
P = VA = 7.4(0.027) = 0.2015... = 0.20 W
150 Ω resistor
V = 7.4(150 / (150 + 240)) = 2.8 V
I = 7.4/390 = 0.01891... = 19 mA
P = I²R = 0.01891²(150) = 0.053661... = 0.05 W
240 Ω resistor
V = 7.4(240 / (150 + 240)) = 4.5394 = 4.5 V
I = 7.4/390 = 0.01891... = 19 mA
P = I²R = 0.01891²(240) = 0.08585... = 0.09 W
verify power consumption
0.55 = 0.21 + 0.20 + 0.05 + 0.09
0.55 = 0.55 **check**
current check through parallel circuits
46 = 27 + 19
46 = 46 **check**
