The equation of the line is y = (3/2)x + 8 if the line that passes through ( - 8, - 4 ) and ( -6, - 1 ).
What is a straight line?
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:
[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]
It is given that:
The line that passes through (-8, - 4 ) and ( -6, - 1)
The standard form of the line in slope-intercept form:
y = mx + c
Here m is the slope of the line
c is the y-intercept.
As we know, the ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).
[tex]\rm m =\dfrac{-1-(-4)}{-6-(-8)}[/tex]
m = 3/2
y = (3/2)x + c
Plug x = -8, y = -4
-4 = (3/2)(-8) + c
c = 8
y = (3/2)x + 8
Thus, the equation of the line is y = (3/2)x + 8 if the line that passes through ( - 8, - 4 ) and ( -6, - 1 ).
Learn more about the straight line here:
brainly.com/question/3493733
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