Question

A vertical pole, 75 feet tall, casts a shadow onto the ground. If the angle of elevation from the tip of the shadow on the ground to the top of the pole is θ=60∘, use the dimensions given to find the length of the shadow, a, to the nearest tenth of a foot. (Do not include units in your answer)

Answer 1

The length of the shadow, h, to the nearest tenth of a foot is 86.6feet

To get the length of the shadow from the given question, we will use the trigonometry SOH CAH TOA

The required setup will give a right-angled triangle.

If a vertical pole, 75 feet tall, casts a shadow onto the ground, the opposite side of the triangle as shown will be 75 feet

The angle of elevation is 60 degrees

The length of the shadow will be the hypotenuse of the triangle as shown:

According to the trigonometry identity:

$sin \theta = \frac{opp}{hyp}\\sin60^0 = \frac{75}{h}\\h = \frac{75}{sin60^0}\\h =\frac{75}{0.8660}\\h= 86.6feet$

Hence the length of the shadow, h, to the nearest tenth of a foot is 86.6feet

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