Question

A motor car is travelling at 144km/h in a 90km/h speed zone .The driver suddenly sees speed camera 80m ahead before the camera can read the cars speed .
Calculate the deceleration required to comply with the speed limit before being caught by the camera

Answer 1

The deceleration required to comply with the speed limit before being caught by the camera is 6.094 meters per square second.

Let assume that the motor car decelerates at constant rate. Given the initial and final speeds ($v_{o}$, $v$), in meters per second, and travelled distance ($s$), in meters, the deceleration ($a$), in meters per square second, is determined by this formula:

$a = \frac{v^{2}-v_{o}^{2}}{2\cdot s}$

If we know that $v_{o} = 25\,\frac{m}{s}$, $v = 40\,\frac{m}{s}$ and $s = 80\,m$, then the deceleration required to comply with the speed limit is:

$a = \frac{\left(25\,\frac{m}{s} \right)^{2}-\left(40\,\frac{m}{s} \right)^{2}}{2\cdot (80\,m)}$

$a = -6.094\,\frac{m}{s^{2}}$

The deceleration required to comply with the speed limit before being caught by the camera is 6.094 meters per square second.

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