Question

One object is thrown vertically upward with an initial velocity of 100 m/s and
another object with an initial velocity of 10 m/s. The maximum height reached
by the first object will be _____
that of the other.
a. 10,000 times
b. none of these
c. 1000 times
O d. 100 times
e. 10 times

Answer 1

We have that for the Question it can be said that The maximum height reached  by the first object will be  100 times  that of the other.

• $(H_{max})_1=100*(H_{max})_2$

From the question we are told

One object is thrown vertically upward with an initial velocity of 100 m/s and  another object with an initial velocity of 10 m/s. The maximum height reached  by the first object will be

that of the other.

a. 10,000 times

b. none of these

c. 1000 times

d. 100 times

e. 10 times

Generally the equation for the velocity is mathematically given as

$v=\frac{d}{t}\\\\Where\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{(V_1)^2}{(v_2)^2}\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{10000}{(10}$

$(H_{max})_1=100*(H_{max})_2$

Therefore

The maximum height reached  by the first object will be  100 times  that of the other.

$(H_{max})_1=100*(H_{max})_2$

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