Question

A newly discovered element named pennsylvaium has the symbol Pn. Pennsylvanium (III)
acetate reacts with ammonium sulfide to produce a precipitate of pennsylvanium (III)
sulfide and aqueous ammonium acetate. Complete the balanced molecular equation

Answer 1

The balanced molecular equation for the reaction that occurs when pennsylvanium (III) acetate reacts with ammonium sulfide to produce a precipitate of pennsylvanium (III) sulfide and aqueous ammonium acetate is:

2 Pn(CH₃COO)₃(aq) + 3 (NH₄)₂S ⇒ Pn₂S₃(s) + 6 NH₄CH₃COO(aq)

Let's consider the unbalanced equation that occurs when pennsylvanium (III) acetate reacts with ammonium sulfide to produce a precipitate of pennsylvanium (III) sulfide and aqueous ammonium acetate. This would be a double displacement reaction.

Pn(CH₃COO)₃(aq) + (NH₄)₂S ⇒ Pn₂S₃(s) + NH₄CH₃COO(aq)

We will balance it using the trial and error method.

• We will balance Pn atoms by multiplying Pn(CH₃COO)₃ by 2.
• We will balance S atoms by multiplying (NH₄)₂S by 3.

2 Pn(CH₃COO)₃(aq) + 3 (NH₄)₂S ⇒ Pn₂S₃(s) + NH₄CH₃COO(aq)

We will get the balanced equation by multiplying NH₄CH₃COO by 6.

2 Pn(CH₃COO)₃(aq) + 3 (NH₄)₂S ⇒ Pn₂S₃(s) + 6 NH₄CH₃COO(aq)

The balanced molecular equation for the reaction that occurs when pennsylvanium (III) acetate reacts with ammonium sulfide to produce a precipitate of pennsylvanium (III) sulfide and aqueous ammonium acetate is:

2 Pn(CH₃COO)₃(aq) + 3 (NH₄)₂S ⇒ Pn₂S₃(s) + 6 NH₄CH₃COO(aq)

Learn more: https://brainly.com/question/7181548