The length of the chord AB of the circle with centre O is 8 cm. The perpendicular drawn from O to the chord, intersects the chord at X, and meets the circle at Y. If XY 3 cm, find the radius of the circle.

Answer:
r = 25/6 cm
Step-by-step explanation:
r = OA
OX = r - 3
Use pythagorean theroem to solve ∆OAX
r^2 = (r - 3)^2 + 4^2
Expand
r^2 = (r^2 - 6r + 9) + 16
Combine like terms
r^2 = r^2 - 6r + 25
Subtract r^2 from both sides
0 = -6r + 25
Add 6r to both sides
6r = 25
Divide both sides by 6
r = 25/6 cm