Anyone gonna try this please!!!!

Explanation:
by the question,
load (L) = 160 N
load distance (LD)= 20m
Effort distance (Ed) = 8m
Effort (E) = ?
we know ,
by using Principle of lever,
[tex]l \times ld = e \times ed \\ 160 \times 20 = e \times 8 \\ e = \frac{160 \times 20}{8} \\ e = 400[/tex]
therefore, the value of effort applied is 400N