A. Rod told you that x + 1 is one of the factors of ax2 – a. Do you agree with him? Why or why not? Write down your step-by-step way of factoring this kind of polynomial. Your answer will be assessed according to this rubrics

Answer:
[tex]a {x}^{2} - a[/tex]
then you multiple the a's
[tex] {x}^{2} - {a}^{2} [/tex]
use square root factor
[tex] \sqrt{ {x}^{2} } + - { \sqrt{a} }^{2} [/tex]
which makes
[tex](x - a)(x + a)[/tex]
then you divide the a by a to get
[tex](x + 1)(x - 1)[/tex]
so yes x + 1 is a factor