Answer:
(i) 5/2 mod 6
5/2 = x
( cross multiply )
2x = 5
( Find the smallest multiple of 5 that can go in both 2 and 5)
The number = 10
2x = 10
(divide both sides by 2 to make x the subject)
x = 5
Ans: 5 mod 6
(ii) 9/7 mod 7
9/7 = x
( cross multiply )
7x = 9
( Find the smallest multiple of 9 that can go in both 7 and 9)
That no = 63
7x = 63
Divide both sides by 7 to make x the subject)
x = 9
Ans: 9 mod 7
(iii) 6/5 mod 7
6/5 = x
( cross multiply )
5x= 6
( Find the smallest multiple of 5 that can go in both 6 and 5)
No: 30
5x = 30
(D.B.S by 6 to make x subject of the formula)
x = 6
Ans: 6 mod 7
