Respuesta :

[tex]\large\underline{\sf{Solution-}}[/tex]

We have to evaluate:

[tex]\sf\dfrac{x^p}{x^p+x^q}+\dfrac{1}{x^{p-q}+1}[/tex]

We know that,

  • [tex]\sf a^{m-n}=\dfrac{a^m}{a^n}[/tex]

So,

[tex]\sf\longmapsto\dfrac{x^p}{x^p+x^q}+\dfrac{1}{x^{p-q}+1}[/tex]

[tex]\sf\longmapsto\dfrac{x^p}{x^p+x^q}+\dfrac{1}{\frac{x^p}{x^q}+1}[/tex]

On taking LCM,

[tex]\sf\longmapsto\dfrac{x^p}{x^p+x^q}+\dfrac{1}{\frac{x^p}{x^q}+1}[/tex]

[tex]\sf\longmapsto\dfrac{x^p}{x^p+x^q}+\dfrac{1}{\frac{x^p+x^q}{x^q}}[/tex]

Now, transposing [tex]\sf x^q[/tex] from denominator to numerator,

[tex]\sf\longmapsto\dfrac{x^p}{x^p+x^q}+\dfrac{1}{\frac{x^p+x^q}{x^q}}[/tex]

[tex]\sf\longmapsto\dfrac{x^p}{x^p+x^q}+\dfrac{x^q}{x^p+x^q}[/tex]

So,

[tex]\sf\longmapsto\dfrac{x^p+x^q}{x^p+x^q}[/tex]

Cancelling [tex]\sf x^p+x^q[/tex] in both denominator and numerator,

[tex]\sf\longmapsto 1[/tex]

Therefore,

[tex]\boxed{\bf \dfrac{x^p}{x^p+x^q}+\dfrac{1}{x^{p-q}+1}=1}\\[/tex]

ACCESS MORE