Acceleration, velocity and displacement are vector quantities while speed and distance are scalar quantities.
The average velocity is defined as the ratio of displacement to time
Displacement= 50 meters to the left
Time = 5 seconds
Velocity = 50 meters/5 seconds = 10 m/s to the left
The average speed of the car is 10 m/s. The difference between velocity and speed is that velocity includes direction while speed does not include direction.
Distance traveled = speed × time
Hence the distance traveled is given by;
Distance = 2.5 m/s × 5 seconds = 12.5 m
Acceleration is defined as ratio of change in velocity to time
Acceleration = change in velocity/time
15 m/s - 0 m/s/5s = 3 m/s^2
Using the equation; v = u + at
u = 18 m/s
v = 0 m/s (when it comes to a stop)
a = -2 m/s^2
t = ?
t = v - u/a
t = 0 m/s - 18 m/s/-2 m/s^2
t = 9 s
From v = u + at
v = 2m/s + (3m/s^2 × 3 s)
v = 2m/s + 9m/s
v = 11 m/s
Using h = ut + 1/2 gt^2
Since it was dropped from a height u = o
h = 1/2 gt^2
h = 1/2 × 10 × (2)^2
h = 20 m
v = u + at
v - u/t = a
a = 24 m/s - 0m/s/4s
a = 6 m/s^2
From;
s = ut + 1/2 at^2
s =[ (+20m/s) × 2s] + 1/2 ( -4m/s^2) (2s)^2
s = 40 - 8
s = 32 m to the right
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