The location of the point (4, 2) is to the right of the triangle RST, therefore,
a dilation from the left or a contraction from the right is required.
The dilation of ΔRST that would result in a line segment with slope of 2
that passes through (4, 2) is C. A dilation with a scale factor of 0.5 centered
at [tex]\underline{(12, \, 2)}[/tex]
Reasons:
The given vertex of the line are;
R(-2, 6), T(-6, -2), S(6, -4)
[tex]The \ slope \ of \ the \ line \ \overline{RT} = \dfrac{6 - (-2)}{-2 - (-6)} = 2[/tex]
Point on the lint RT that has the same y-coordinate as the point (4, 2) is (-4, 2)
Taking the center of dilation as the point (12, 2), we have;
Coordinates of the point (-4, 2) relative to the point (12, 2) is found as
follows;
(-4 - 12, 2 - 2) = (-16, 0)
Therefore, dilating (-16, 0) by [tex]\overline {RT}[/tex] a scale factor of 0.5, with a center at (12,
2) gives;0.5 × (-16, 0) = (-8, 0)
The actual location of the point (-8, 0) is (-8 + 12, 0 + 2 ) = (4, 2)
Therefore, the dilation of ΔRST that would result in a line segment with
slope of 2 that passes through (4, 2) is C. A dilation with a scale factor of 0.5 centered at [tex]\underline{(12, \, 2)}[/tex]
Learn more here:
https://brainly.com/question/21922707