Question

Janet jumps horizontally off a high diving platform with a velocity of 2.08 m/s and lands
in the water 2.8 s later.
How high is the platform? The acceleration
of gravity is 9.8 m/s2

Answer 1

Answer:

Below

Explanation:

To find the height of the diving platform we can use this formula :

     $dy= \frac{t^2(g)}{2} \\dy = \frac{2.8^2(9.8)}{2} \\dy = 76.832 / 2 \\dy = 38.4 m \\dy = 38 m$

Therefore the height of the diving platform is 38m

hope this helps!