Question

An autographed baseball rolls off of a 0.99 m high desk and strikes the floor 0.34 m away
from the desk.
How fast was it rolling on the desk before it fell off? The acceleration of gravity is 9.81 m/s2

Answer 1

Answer:

Below

Explanation:

First, we need to find the time of flight of this projectile :

     $t=\sqrt{\frac{2dy}{g} }$

     $t =\sqrt{\frac{2(0.99)}{9.81}$

     $t =\sqrt{\frac{1.98}{9.81}$

     $t =\sqrt{0.20183486238}$

     $t = 0.448489506$ $seconds$

Now we can use this formula to find the initial horizontal velocity :

     $Dhorizontal = Vhorizontal (time)$

     $0.34 m = Vx(0.448489506) \\0.76m/s^2 = Vx$

Therefore the initial velocity of the baseball was 0.76 m/s^2 [Forward]

Hope this helps! Best of luck <3