Question

For three consecutive homework assignments, each assignment had one more question than the previous assignment. The total number of questions on the three assignments is greater than 51 a.Write an inequality to represent this situation, where q is the number of questions on the first assignment

Answer 1

The inequality that represents the situation is:

$3q + 3 > 51$

The first assignment had at least 17 questions.

• On the first assignment, there were q questions.
• Each assignment had one more question than the previous one, so the second had q + 1 questions and the third had q + 2 questions.

The total number of questions is:

$T = q + q + 1 + q + 2 = 3q + 3$

Since the total is greater than 51, the inequality is:

$3q + 3 > 51$

Solving the inequality, we have that:

$3q > 48$

$q > \frac{48}{3}$

$q > 16$

Thus, it is found that the first assignment had at least 17 questions.

A similar problem is given at https://brainly.com/question/24514895