Respuesta :

Answer:

x^3+3x^2+2x+1-x^2=x^3+x^2-x^2

Step-by-step explanation:

x^3+3x^2+3x+1=x^3+x^2+x

x^3+3x^2+3x+1-x=x^3+x^2+x-x

x^3+3x^2+2x+1=x^3+x^2

x^3+3x^2+2x+1-x^2=x^3+x^2-x^2

x^3+2x^2+2x+1=x^3

x^3+2x^2+2x+1-x^3=x^3-x^3

2x^2+2x+1=0

x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:2\cdot \:1}}{2\cdot \:2}

x_1=\frac{-2+2i}{2\cdot \:2},\:x_2=\frac{-2-2i}{2\cdot \:2}

\frac{-2+2i}{2\cdot \:2}

=\frac{-2+2i}{4}

\frac{-2-2i}{2\cdot \:2}

=\frac{-2-2i}{4}

=-\frac{1+i}{2}

-2-2i

=-2\cdot \:1-2i

=-2\left(1+i\right)

=-\frac{2\left(1+i\right)}{4}

-\frac{1+i}{2}

x=-\frac{1}{2}+i\frac{1}{2},\:x=-\frac{1}{2}-i\frac{1}{2}

Multiply: (x+1) (x+1) (x+1) and then you’ll get your answer
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