Respuesta :
Answer:
x^3+3x^2+2x+1-x^2=x^3+x^2-x^2
Step-by-step explanation:
x^3+3x^2+3x+1=x^3+x^2+x
x^3+3x^2+3x+1-x=x^3+x^2+x-x
x^3+3x^2+2x+1=x^3+x^2
x^3+3x^2+2x+1-x^2=x^3+x^2-x^2
x^3+2x^2+2x+1=x^3
x^3+2x^2+2x+1-x^3=x^3-x^3
2x^2+2x+1=0
x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:2\cdot \:1}}{2\cdot \:2}
x_1=\frac{-2+2i}{2\cdot \:2},\:x_2=\frac{-2-2i}{2\cdot \:2}
\frac{-2+2i}{2\cdot \:2}
=\frac{-2+2i}{4}
\frac{-2-2i}{2\cdot \:2}
=\frac{-2-2i}{4}
=-\frac{1+i}{2}
-2-2i
=-2\cdot \:1-2i
=-2\left(1+i\right)
=-\frac{2\left(1+i\right)}{4}
-\frac{1+i}{2}
x=-\frac{1}{2}+i\frac{1}{2},\:x=-\frac{1}{2}-i\frac{1}{2}