Question

Find the Force of gravity between a 55-kg person and their 2.0-kg sandwich that is held 0.25 meters away.
(I end up getting a 1.17392*1m^-7

9.8

5.9 x 10-8

220

880

Answer 1

The force of gravity between the person and the sandwich is 1.17×10¯⁷ N

From the question given above, the following data were obtained:

Mass of person (M₁) = 55 Kg

Mass of sandwich (M₂) = 2 Kg

Distance apart (r) = 0.25 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force (F) =?

Th force of gravity between the person and the sandwich can be obtained as follow:

$F = \frac{GM_{1} M_{2}}{r^{2}} \\\\ F = \frac{6.67*10^{-11} * 55 * 2}{0.25^{2}}$

F = 1.17×10¯⁷ N

Therefore, the force of gravity between the person and the sandwich is 1.17×10¯⁷ N

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Answer 2

The force of gravity between the two individuals is $1.17 \times 10^{-7} \ N$

The given parameters;

• mass of the individuals, = 55 kg, 2.0 kg
• distance between the two persons, = 0.25 m

The force of gravity between the two individuals is calculated by applying Newton's law of universal gravitation as follows;

$F = \frac{Gm_1 m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11}) \times 2\times 55}{0.25^2} \\\\F = 1.17\times 10^{-7} \ N$

Thus, The force of gravity between the two individuals is $1.17 \times 10^{-7} \ N$

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