Answer:
70 f^6 g^2 - h
Step-by-step explanation:
10f^2gh, 35f^3g^2 = lcm = 10 and 35 = 10/35 = 0.285714286 multiplier 0.285714286 * ( 35/2) = 5 then 35/5 = 7 then multiply by 10 = 70 or you need to add up prime of product remainders and similar as counted as = (1 * similar) f^2 and f^3 is the sae as 2 and 3 = 6 = f^6 and g^1 and g^2 = 1 and 2 = 2 =^2 then -h Note when working with 2 lots of unit numbers to find the lowest multiple it only works to see the prime of products are 2+3 = 6 while greatest multiple of 2 + 3 = 1 so 3+4 = 1 too for greatest multiple while 3 +4 = 12 we show as 3 *4 = 12 and 2*3 = 6 for lowest multiple's
