Question

(ill give you brainliest if u can answer this)
The Marble Club has six members. Each member contributes his marbles and holds office on the basis of the number of marbles he contributes. The president has contributed 104 marbles more than the vice-president, who in turn has contributed 203 more than the treasurer. The secretary donated 1/2 the amount of the vice-president. The marble counter contributed 3 more than the sergeant at arms, and they have contributed 485 marbles together. If the total number of marbles is 3,886, how many did each contribute?

Answer 1

Answer:

mable counter =244

sergeant at arms =241

president =1424

Vice president =1320

treasurer= 1117

Secretary =660

Step-by-step explanation:

alright so here is what we know

President = Vice president's + 104

Vice president =treasurer's +203

Secretary = 1/2 of Vice president's

marble counter = sergeant in Arms + 3

Marble counter +Sergeant in Arms =485

the initials will be used further on

485÷2= 242.5

but we know that 1.5+1.5=3 which makes it up the 3 therefore we will be left with 241 for SA and 244 for MC

now we subtract 485 from the total 3886 contributed so that we remain with the contributions of the other 4 since we already have for MC and SA =3404

now we know

P=(T+203)+104

VP=T+203

S=1/2(T+203)

we have not been give for T

so we creat a formular to find T

[(T+203)+104] + [1/2(T+203)] + T+203=3404

this can be worked out and the answer will be

T=1117

Now we go and substitute for T in the equation for P, VP and S

P=1117+203+104=1424

VP =1117+203= 1320

S=1/2(1117+203)= 660