Question

The functions s and t are defined as follows.
s(x) = -x+1
t(x)=x2-1
Find the value of s(t(2)).
s(t (2)) =

The 2 next to the x is an exponent

Answer 1

Answer:

$s(x) = - x + 1 \\ t(x) = {x}^{2} - 1 \\ s(t(x)) = - ({x}^{2} - 1) + 1 \\ = - {x}^{2} + 1 + 1 \\ = 2 - {x}^{2} \\ s(t(2)) = 2 - {2}^{2} \\ \boxed{s(t(2)) = - 2}$