Answer:
Step-by-step explanation:
The slope of a perpendicular line, to one that has slope of 2, is the negative inverse of the reference slope. The negative inverse of 2 is -(1/2). The perpendicur line will have the form y = -(1/2)x + b, where b is the y-intercept. Any value of b will produce a perpendicular line to one that has slope of 2, but this line needs to go through point (0,-3). To find the value of b that would make this happen, just use that point in the equation y = -(1/2)x + b and solve for b:
y = -(1/2)x + b
-3 = -(1/2)*(0) + b
b = -3
The equation becomes y = -(1/2)x - 3
I graphed this versus a line with slope 2 and y-intercept of 2: y=2x+2
