Using the binomial probability concept, the probability of having exactly 1 hit in his next 7 at bats is 0.324
Recall :
- P(x = x) = nCx * p^x * q^(n-x)
- p = probability of success = 0.24
- n = number of trials = 7
- q = 1 - p = 1 - 0.24 = 0.76
P(X = 1)= 7C1 × 0.24¹ × 0.76^6
P(X = 1) = 7 × 0.24 × 0.192699928576
P(X = 1) = 0.324
Therefore, the probability of having exactly 1 hit is 0.324
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