1.
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y= -2/3x + 9; (-6, 5)

1 Write the equation of a line that is perpendicular to the given line and that passes through the given point y 23x 9 6 5 class=
1 Write the equation of a line that is perpendicular to the given line and that passes through the given point y 23x 9 6 5 class=
1 Write the equation of a line that is perpendicular to the given line and that passes through the given point y 23x 9 6 5 class=
1 Write the equation of a line that is perpendicular to the given line and that passes through the given point y 23x 9 6 5 class=
1 Write the equation of a line that is perpendicular to the given line and that passes through the given point y 23x 9 6 5 class=

Respuesta :

Answer:

A. y = (-3/2)x-4

Step-by-step explanation:

The perpendicular equation is y = -3/2x - 4.

You can find this by first realizing that perpendicular lines have opposite and reciprocal slopes. So since it starts at 2/3 we flip it and make it a negative and the new slope is -3/2. Now we can use that and the point to get the y intercept using slope intercept form.

y = mx + b

5 = (-3/2)(-6) + b

5 = 9 + b

-4 = b

And now we can use our new slope and new intercept to model the equation.

y = -3/2x - 4

Hay dear friend thank you for asking the question

according to the question we know that

y = mx +b

And given that y = 5 , m = -3/2, x = -6

so

5 = -3/2×(-6) +b

5 = 9 + b

-4 = b

now we can use our new slope and new intercept model equation then,

y = (-3/2)x-4

I hope it's help you

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