Since the molarity of the acid is 4.8 M, it is discharged and it needs to be recharged.
The equation of the reaction is;
H2SO4(aq) + 2NaOH(aq) --------> Na2SO4(aq) + 2H2O(l)
From the question we know that;
Concentration of base (CB) = 0.621 M
Volume of base (VB) = 31.26 ml
Volume of acid (VA) = 2.00 ml
Concentration of acid (CA) = ?
From the reaction equation;
Number of moles of acid (NA) = 1
Number of moles of base (NB) = 2
Using the titration formula;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CA = CBVBNA/VANB
CA = 0.621 M × 31.26 ml × 1/2.00 ml × 2
CA = 4.8 M
Since the molarity of the acid is 4.8 M, it is discharged and it needs to be recharged.
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