. Write an equation of the line that is parallel to the line whose equation is 3y + 7 = 2x and passes through the point (2,6) both slope-intercept form and point-slope form.

Respuesta :

The equation in slope intercept form is y = 2/3x + 14/3 and the equation in point slope form is y  - 6 = 2/3(x - 2)

How to determine the equation of the line?

The equation of the line is given as:

3y + 7 = 2x

Subtract 7 from both sides

3y = 2x - 7

Divide both sides by 3

y = 2/3x - 7/3

Both lines are parallel.

So, they have the same slope

This means that the slope of the line is:

m = 2/3

The point slope form of a linear equation is represented as:

y - y1 = m(x - x1)

The line is said to pass through the point (2,6).

This means that (x1,y1) = (2,6)

Substitute (x1,y1) = (2,6) and m = 2/3 in the equation y - y1 = m(x - x1)

This gives

y  - 6 = 2/3(x - 2)

Add 6 to both sides

y = 2/3(x - 2) + 6

Expand

y = 2/3x - 4/3 + 6

Evaluate the sum and difference

y = 2/3x + 14/3

Hence, the equation in slope intercept form is y = 2/3x + 14/3 and the equation in point slope form is y  - 6 = 2/3(x - 2)

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