The final velocity of the ball before it hits the ground is 34.3 m/s.
The given parameters;
- height of the rock, h = 60 m
The final velocity of the ball before it hits the ground is calculated as follows;
v² = u² + 2gh
where;
v is the final velocity of the ball
u is the initial velocity of the ball
v² = 0 + 2gh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 60)
v = 34.3 m/s
Thus, the final velocity of the ball before it hits the ground is 34.3 m/s.
Learn more here:https://brainly.com/question/1712244
