Question

A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a
force of 80.0 N. What is the magnitude of the normal force acting on the block? *
O 16 N
ON
49 N
5 N

Answer 1

The magnitude of the normal force acting on the block is: C. 49 N

Given the following data:

• Mass of block = 5.0 kg

• Force = 80 Newton

We know that acceleration due to gravity (g) for a block being pushed on a frictionless surface is equal to 9.8 meter per seconds square.

To find the magnitude of the normal force acting on the block:

A normal force can be defined as the force being exerted by a surface on an object such as a block.

Mathematically, the normal force is given by the formula:

$F_N = mg$

Where:

• m is the mass of an object.

• g is the acceleration due to gravity.

• $F_N$ is the normal force.

Substituting the given parameters into the formula, we have;

$F_N = 5\times9.8$

Normal force = 49 Newton

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