Question

A 50.-Newton horizontal force is needed to keep an object weighing 500. Newtons moving at a constant velocity of 2.0 meters per second across a horizontal surface. The magnitude of the frictional force acting on the object is

Answer 1

-- "Constant velocity" means the acceleration of the object is zero.

-- "Zero acceleration" means that all the forces on the object add up to zero.

-- If a force of 50-newtons is pulling the object in one direction
and the object's speed is constant, then the frictional force on
the object must be 50 newtons in the opposite direction.

Answer 2

The magnitude of the frictional force acting on the object is 50 N.

Given :

Horizontal Force = 50 N

Object weight = 500 N

Constant Velocity = 2 m/sec

Solution --

Constant velocity means acceleration is zero. And from Newton's second law of motion,

$\rm \sum F = ma$  ---- (1)

Here a = 0, therefore from equation (1) we get:

$\rm \sum F = 0$

$\rm F_1 - 50 = 0$

where $\rm F_1$ is friction force,

$\rm F_1 = 50 \;N$

The magnitude of the frictional force acting on the object is 50 N.

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https://brainly.com/question/23073749