Consider the following equations:
y1 = 2x + 7
y2 = 1.5x + 4
Compare the values of y1 and y2 for x < −7 and for x > −5. Create a table and solve this system of equations.

Respuesta :

The solution of the system of equation is given by the point where the

ordered pair of each equation are equal.

The solution of the equation system is x = -6

Reasons:

y₁ = 2·x + 7

y₂ = 1.5·x + 4

The values of y₁ for x < -7  are;

y₁₍₋₈₎ = 2 × (-8) + 7 = -9

y₁₍₋₉₎ = 2 × (-9) + 7 = -11

y₁₍₋₁₀₎ = 2 × (-10) + 7 = -13

Therefore, we get;

The values of y₁ for x < -7 = -9, -11, -13,...

The values of y₂ for x < -7  are;

y₂₍₋₈₎ = 1.5 × (-8) + 4 = -8

y₂₍₋₉₎ = 1.5 × (-9) + 4 = -9.5

y₂₍₋₁₀₎ = 1.5 × (-10) + 4 = -11

The values of y₂ for x < -7  are; -8, -9.5, -11

The values of y₁ for x > -5  are;

y₁₍₋₄₎ = 2 × (-4) + 7 = -1

y₁₍₋₃₎ = 2 × (-3) + 7 = 1

y₁₍₋₂₎ = 2 × (-2) + 7 = 3

Therefore, we get;

The values of y₁ for x > -5 = -1, 1, 3

The values of y₂ for x > -5  are;

y₂₍₋₄₎ = 1.5 × (-4) + 4 = -2

y₂₍₋₃₎ = 1.5 × (-3) + 4 = -0.5

y₂₍₋₂₎ = 1.5 × (-2) + 4 = 1

The values of y₂ for x > -5  are; -2, -0.5, 1, ...

The table is presented as follows;

[tex]\begin{tabular}{|c|r|r|}x&y_1&y_2\\-2&3&1\\-3&1&-0.5\\-4&-1&-2\\-5&-3&-3.5\\-6&-5&-5\\-7&-7&-6.5\\-8&-9&-8\end{array}\right][/tex]

From the above table the solution to the system of equation (the value of x

at which y₁ = y₂) is x = -6.

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