The solution of the system of equation is given by the point where the
ordered pair of each equation are equal.
The solution of the equation system is x = -6
Reasons:
y₁ = 2·x + 7
y₂ = 1.5·x + 4
The values of y₁ for x < -7 are;
y₁₍₋₈₎ = 2 × (-8) + 7 = -9
y₁₍₋₉₎ = 2 × (-9) + 7 = -11
y₁₍₋₁₀₎ = 2 × (-10) + 7 = -13
Therefore, we get;
The values of y₁ for x < -7 = -9, -11, -13,...
The values of y₂ for x < -7 are;
y₂₍₋₈₎ = 1.5 × (-8) + 4 = -8
y₂₍₋₉₎ = 1.5 × (-9) + 4 = -9.5
y₂₍₋₁₀₎ = 1.5 × (-10) + 4 = -11
The values of y₂ for x < -7 are; -8, -9.5, -11
The values of y₁ for x > -5 are;
y₁₍₋₄₎ = 2 × (-4) + 7 = -1
y₁₍₋₃₎ = 2 × (-3) + 7 = 1
y₁₍₋₂₎ = 2 × (-2) + 7 = 3
Therefore, we get;
The values of y₁ for x > -5 = -1, 1, 3
The values of y₂ for x > -5 are;
y₂₍₋₄₎ = 1.5 × (-4) + 4 = -2
y₂₍₋₃₎ = 1.5 × (-3) + 4 = -0.5
y₂₍₋₂₎ = 1.5 × (-2) + 4 = 1
The values of y₂ for x > -5 are; -2, -0.5, 1, ...
The table is presented as follows;
[tex]\begin{tabular}{|c|r|r|}x&y_1&y_2\\-2&3&1\\-3&1&-0.5\\-4&-1&-2\\-5&-3&-3.5\\-6&-5&-5\\-7&-7&-6.5\\-8&-9&-8\end{array}\right][/tex]
From the above table the solution to the system of equation (the value of x
at which y₁ = y₂) is x = -6.
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