Considering the equation for the rate, it is found that it is of [tex]9 \times 10^5[/tex] kilometres per year.
The rate is distance divided by time, that is:
[tex]r = \frac{d}{t}[/tex]
In this problem:
The rate is:
[tex]r = \frac{d}{t} = \frac{2.025 \times 10^{14}}{2.25 \times 10^8} = 0.9 \times 10^6 = 9 \times 10^5[/tex]
The rate is of [tex]9 \times 10^5[/tex] kilometres per year.
A similar problem is given at https://brainly.com/question/24316569