Question

Find the slope of any line perpendicular to the line through (4,0) and (-6,1)

Answer 1

Answer:

$\sf\dfrac{1}{10}$

Step-by-step explanation:

We need to find out the slope of the line perpendicular to the given points . We know that ,

$\sf: \implies Slope =\dfrac{y_2-y_1}{x_2-x_1} \\\\\sf : \implies Slope = \dfrac{-6-4}{1-0} \\\\\sf : \implies Slope =\dfrac{-10}{1} \\\\\sf : \implies \boxed{\sf Slope = -10}$

Again we know that the product of slopes of two perpendicular lines is -1 . Therefore ,

$\sf: \implies m_{perp}= \dfrac{-1}{-10}\\\\\sf : \implies \boxed{\boxed{\sf\pink{ Slope_{perp}= \dfrac{1}{10}}}}$