Question

A particular beer is 6.50 % ethanol by volume . If a single bottle of beer contains a total of 750.0 mL of beer, what volume, in mL of ethanol (C2H6O), are present in the bottle?

Answer 1

This question involves the simple concept of percent by volume in a solution.

The volume of ethanol present in the bottle is found to be "48.75 ml".

The percent by volume of a solution means the amount of that substance present in the solution, represented as a fraction of the total volume of the solution. Hence, the volume of ethanol present in the bear can be found by using the following formula:

$Percent\ by\ Volume\ of\ Ethanol = \frac{Volume\ of Ehanol}{Total\ Volume\ of\ Beer}(100\ \%)\\\\6.50\ \% = \frac{V}{750\ mL}(100\ \%)\\\\V = \frac{(6.50\ \%)(750\ mL)}{100\ \%}$

V = 48.75 mL

Learn more about percent by volume here:

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