Ace and Annies' graphs are illustrations of linear functions.
(a) Equation of each line
The points on Ace's line are: (0,2) and (7,9)
The slope (m) is calculated as:
[tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex]
So, we have:
[tex]\mathbf{m = \frac{9 - 2}{7- 0} = 1}[/tex]
The equation is then calculated as:
[tex]\mathbf{y = m(x - x_1) + y_1}[/tex]
This gives
[tex]\mathbf{y = 1(x - 0) + 2}[/tex]
[tex]\mathbf{y = x + 2}[/tex]
The points on Annie's line are: (0,8) and (6,2)
The slope (m) is calculated as:
[tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex]
So, we have:
[tex]\mathbf{m = \frac{2 - 8}{6- 0} = -1}[/tex]
The equation is then calculated as:
[tex]\mathbf{y = m(x - x_1) + y_1}[/tex]
This gives
[tex]\mathbf{y = -1(x - 0) + 8}[/tex]
[tex]\mathbf{y = -x + 8}[/tex]
So, we have:
- The equation of Ace's line is: [tex]\mathbf{y = x + 2}[/tex]
- The equation of Annie's line is: [tex]\mathbf{y = -x + 8}[/tex]
(b) The ordered pair where the lines intersect
The lines intersect at x = 3 and y = 5.
So, the ordered pair where the lines intersect is (3,5)
(c) Is the ordered pair a solution to Ace's equation
Yes, the ordered pair is a solution to Ace's equation
This is so because:
- The ordered pair satisfies the equation [tex]\mathbf{y = x + 2}[/tex]
- The line of [tex]\mathbf{y = x + 2}[/tex] passes through the point
(d) Is the ordered pair a solution to Annie's equation
Yes, the ordered pair is a solution to Annie's equation
This is so because:
- The ordered pair satisfies the equation [tex]\mathbf{y = -x + 8}[/tex]
- The line of [tex]\mathbf{y =- x + 8}[/tex] passes through the point
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