Question

Please Help ~ 50 Points!
A bunjee jumper steps off a bridge and experiences 2.34 seconds of free fall. How far has the jumper fallen? How fast is the jumper going after 2.34 seconds?

The jumper has fallen __________ .
The jumper has a speed of __________ after 2.34 seconds.

Answer 1

Answer:

height=.5*gravity*(time)^2

height=0.5*9.81*(2.34)^2

height= 26.85m

------

velocity= gravity*time

velocity = 9.81 * 2.34

velocity= 22.95 m/s

Answer 2

• Time=t=2.34s
• Acceleration=g=10m/s^2
• Height=h
• Final velocity=v

$\\ \sf\longmapsto h=-\dfrac{1}{2}gt^2$

$\\ \sf\longmapsto h=-5(2.34)^2$

$\\ \sf\longmapsto h=-5(5.47)$

$\\ \sf\longmapsto h=27.35m$

And

$\\ \sf\longmapsto v^2=u^2+2gs$

$\\ \sf\longmapsto v^2=(2.34)^2+2(10)(27.35)$

$\\ \sf\longmapsto v^2=5.47+547$

$\\ \sf\longmapsto v^2=552.47$

$\\ \sf\longmapsto v\approx 23.5m/s$