Question

what is the molarity of an hcl solution if 50.0 ml is neutralized in a titration by 40.0 ml of 0.400 m naoh? group of answer choices 0.200 m 0.280 m 0.320 m 0.500 m

Answer 1

The molarity of an HCl solution if 50.0 ml is neutralized in a titration by 40.0 ml of 0.400M NaOH is 0.320 M.

HOW TO CALCULATE MOLARITY:

• The Molarity of an acid when involved in a titration procedure can be calculated by using the formula below:

M1V1 = M2V2

Where;

1. M1 = molarity of acid (M)
2. M2 = molarity of base (M)
3. V1 = volume of acid (mL)
4. V2 = volume of base (mL)

According to this question,

1. M1 = ?
2. M2 = 0.400M
3. V1 = 50 mL
4. V2 = 40 mL

M1 × 50 = 0.400 × 40

50M1 = 16

M1 = 16 ÷ 50

M1 = 0.32M

• Therefore, the molarity of an HCl solution if 50.0 ml is neutralized in a titration by 40.0 ml of 0.400M NaOH is 0.32 M.

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