Consider the line y-2x+9
Find the equation of the line that is perpendicular to this line and passes through the point (7, -6)

Find the equation of the line that is parallel to this line and passes through the point (7, -6)

Respuesta :

Answer:

Step-by-step explanation:

A line that is perpendicular will have a slope that is the negative inverse of the reference line slope.  Rewrite y-2x+9=0 as y =mx+b:

y = 2x-9   This line has a slope of 2 and a y-intercept of -9.  A perpendicular line to this will have a slope that is the negative inverse of 2, that is, -(1/2).

y=-(1/2)+b

We don't know b, but can find it by entering the x and y for the known point and solve for b:

Point:  (7, -6)

y=-(1/2)+b  

-6 = -(1/2)*(7)+b

-6 = -(7/2) + b

b = -6 + (7/2)

b = -2.5

The equation is y = -(1/2)x - 2.5

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