Ca(s) + 2H2O(l) --->Ca(OH)2(aq) + H2(g)
1 : 2 1 : 1
n H2O = 0.15 moles
for every 2mole ratio of H2O = 0.15 moles
relate to the mole ratio of calcium hydroxide.
2 mole ratio = 0.15moles
1 mole ratio = ?
= 0.075 moles.
from,
n = mass/molar mass
Molar mass of Ca(OH)2 = 74g/mol
n Ca(OH)2 = 0.075moles
m Ca(OH)2 = 74*0.075
m Ca(OH)2 = 5.55grams.
The grams of calcium hydroxide formed are 5.55g.
