Answer:
• The quadratic formular is as below:
[tex]{ \boxed{ \rm{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }}}[/tex]
• Basing on our equation given, x² - 5x - 2 = 0;
[tex]{ \rm{x = \frac{ - ( - 5) \pm \sqrt{ {( - 5)}^{2} - (4 \times 1 \times - 2) } }{(2 \times 1)} }} \\ \\ { \rm{x = \frac{5 \pm \sqrt{33} }{2} }} [/tex]
• Therefore;
[tex]{ \boxed{ \rm{x = \frac{5 + \sqrt{33} }{2} }}}{ \rm{ \: \: or \: \: }}{ \boxed{ \rm{x = \frac{5 - \sqrt{33} }{2} }}} \\ \\ { \boxed{ \boxed{ \rm{x = 5.37 \: \: or \: \: - 0.37}}}}[/tex]