Question

Express (w+7)(w-2) =0 in standard form​

Answer 1

$(w + 7)(w - 2)$

$w(w - 2) + 7(w - 2)$

${w}^{2} - 2w + 7w - 14$

${w}^{2} + 5w - 14$

Answer 2

Answer:

${w}^{2} + 5w - 14= 0$

Step-by-step explanation:

$(w + 7)(w - 2) = 0 \\ w(w - 2) + 7(w - 2) = 0 \\ {w}^{2} - 2w + 7w - 14 = 0 \\ {w}^{2} + 5w - 14= 0$