Answer:
[tex]p(t) = - 3t + 75 \\ p(t) = 0 \\ - 3t + 75 = 0 \\ 3t = 75 \\ t = \frac{75}{3} \rightarrow \boxed{t = 25 \: mins} \\ 3 \: papers \: per \: mins \\ domain \: \boxed{t \geqslant 0} \: \\ because \: time \: cant \: be \: negative \: on \\ \: this \: perticular \: occasion \\ \therefore \: range \: \boxed {p(t) \geqslant 0 }[/tex]
