Question

Geometry questions!! ​

Answer 1

Answer:

Step-by-step explanation:

3) In ΔBCD,

∠D = ∠C = 70     {Isosceles triangle}

∠DCB + ∠D + ∠C = 180

∠DCB  + 70 + 70  = 180

∠DCB + 140 = 180

∠DCB = 180 - 140

∠DCB = 40°

x = 360 - (∠DCB + ∠CBA)

  = 360 -( 40 + 40)

 = 360 - 80

x = 280

4) BCD is an equilateral triangle

∠CBD = 60°

x = 360 - (280+ 60)

  = 360 - (340

x = 20°

Answer 2

Step-by-step explanation:

I∆BCD is isosceles triangle ..

so there ,

angle BDC = angle BCD= 70°

2*70° + DBC= 180°

angle DBC = 180°- 140°

= 40°

40°+40° + x = 360°

X= 360°- 80°

= 280°