The data below gives the delivery times of a local pizza delivery place in minutes).
18, 69, 22, 27, 32, 25, 16, 25
Question 2
10 pts
State the value for each item listed below. Round all values to the tenth place. If the value does not
exist, type none.
Mean
Median
Mode
Outlier
Range

The data below gives the delivery times of a local pizza delivery place in minutes 18 69 22 27 32 25 16 25 Question 2 10 pts State the value for each item liste class=

Respuesta :

Answers:

  • Mean = 29.3
  • Median = 25
  • Mode = 25
  • Outlier = 69
  • Range = 53

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Explanation:

To find the mean, we add up all the values

18+69+22+27+32+25+16+25 = 234

Then we divide that result by n = 8 since there are 8 values in this list

234/n = 234/8 = 29.25 which is the mean. This value rounds to 29.3 when rounding to the nearest tenth.

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Now onto the median. We first need to sort the items from smallest to largest

This list

{18, 69, 22, 27, 32, 25, 16, 25}

sorts to

{16, 18, 22, 25, 25, 27, 32, 69}

Since n = 8 is an even number, the median will be between two values

It's between the items at slot 4 and 5. Note that n/2 = 8/2 = 4 to help determine that first slot mentioned.

The items in slots 4 and 5 are 25 and 25. In this case, we get the same value but that won't happen every time. Averaging those two values gets us 25.

The median is 25.

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The mode is the most frequent value. In this case that would be 25 since it shows up the most (twice) compared to the other values (which only show up once).

Notes:

  • It's possible to have more than one mode, and it's also possible to not have any modes at all. In this case, we only have exactly one mode.
  • In this case, the median and mode are the same value. This won't always happen.

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Before we determine anything about outliers, we need to calculate the standard deviation. You'll need your calculator for this one. You can do so by hand, but it's tedious busywork in my opinion.

Use a calculator to find the standard deviation of the given list is approximately 15.746031246

If we started at the center median value of 25, and added on 1.5 times the standard deviation, then we get to:

median+1.5*stdDev = 25+1.5*15.746031246 = 48.619046869

This value is the upper fence. It's the boundary between non-outliers and large outliers. Anything beyond 48.619046869 will be a large outlier. This applies to the value 69 from the original list. This value is effectively an "island" point far from the "mainland" of the cluster of other points.

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Luckily, we don't need a calculator for this part. Subtract the max and min to get the range

range = max - min = 69 - 16 = 53

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