Geometric optics allow to describe all the characteristics of the image formed by the concave mirror are:
- The distance to the image is: q = 0.9 m.
- The magnification is: m = -0.5X
Geometric optics describes the position and height of objects and their images formed by lenses and mirrors, that description is made by the expressions.
Constructor equation [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
magnification [tex]m = \frac{h'}{h}= - \frac{q}{p}[/tex]
Where f is the focal length, p and q the distance to the object and the image, respectively, m the magnification, h and h' the height of the object and the image, respectively.
In this case it indicates that the focal length is 0.6 m and the distance to the object (p) is 1.8 m, let's find the distance to the image, in the attachment we have a schema of the system.
[tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}\\\frac{1}{q}= \frac{1}{0.6} - \frac{1}{1.8} \\\frac{1}{q} = 1.111[/tex]
q = 0.9 m
Let's find the magnification
m = [tex]- \frac{0.9}{1.8}[/tex]
m = - 0.5 X
The negative sign indicates that the image is real and the value that the image is smaller than the object.
Geometric optics allow to describe all the characteristics of the image formed by the concave mirror are:
- The distance to the image q = 0.9 m
- The magnification m = -0.5X
Learn more here: brainly.com/question/15850239
