Question

Velocity and Acceleration Quick Check
Item 1
Item 2
Item 3
Use the equation for motion to answer the question.
1 = 10 + vot+ jat
An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which
option shows the final position of the object after 1 s?
Item 4
(1 point)
• 17 m
o 60 m
0 32 m
O 30 m
so

Answer 1

Answer:

• 17 m

o 60 m

Explanation:

Answer 2

The final position of the object at the given time is 17.0 m.

The given parameters:

• initial position of the object, x₀ = 2 m
• initial velocity of the object, u = 15 m/s
• time of motion, t = 1 s

The final position of the object at the given time is calculated as follows;

$x= x_0 + v_0t + \frac{1}{2} at^2$

where;

a is the acceleration of the object

At constant velocity, acceleration = 0

$x= 2 \ + \ 15(1) + \frac{1}{2} (0)(1)^2\\\\x = 17.0 \ m$

Thus, the final position of the object at the given time is 17.0 m.

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