Question

PLEASE HELP
A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land

Answer 1

Answer:

Explanation:

It is hard to imaging that wind resistance is not a factor for such a low mass ball, but we must make that assumption on the first estimate.

s = s₀ + v₀t + ½at²

vertical analysis with floor level as origin

0 = 1.2 + 5t + ½(-9.8)t²

0 = 1.2 + 5t - 4.9t²

quadratic formula positive answer

t = (-5 - √(5² - 4(-4.9)(1.2))) / (2(-4.9))

t = 1.22 s is the flight time

horizontal analysis with launcher as origin

s = 0 + 12(1.22) + ½(0)1.22²

s = 14.6517... 15 m