Respuesta :
Answer:
1. (3bc)^2
2. (10mn^3)^2
3.
b^9
------- ( as a fraction the top number is b^9 and the bottom is 125)
125
Step-by-step explanation:
its hard to explain sorry but if you really want to know just comment and ill provide another answer sorry again. but i can explain the last one, so to find the cube you have to multiply that one side by the power of three, so if it was 4, you would do 4^3, but since its 1/5b^3, it would be (1/5b^3)^3
hope this rlly helps
:)
A monomial is an expression that has a single term.
(a) 9b^2c^2 and 100m^2n^6
We have:
[tex]\mathbf{9b^2c^2}[/tex]
Express 9 as 3^2
[tex]\mathbf{9b^2c^2 = 3^2b^2c^2}[/tex]
Factor out the squares
[tex]\mathbf{9b^2c^2 = (3bc)^2}[/tex]
Similarly;
[tex]\mathbf{100m^2n^6}[/tex]
Express 100 as 10^2 and n^6 as n^3^2
[tex]\mathbf{100m^2n^6 = 10^2m^2(n^3)^2}[/tex]
Factor out the squares
[tex]\mathbf{100m^2n^6 = (10mn^3)^2}[/tex]
Hence, 9b^2c^2 and 100m^2n^6 as squares are: [tex]\mathbf{(3bc)^2}[/tex] and [tex]\mathbf{(10mn^3)^2}[/tex]
(b) -a^3b^6 and -27x^6b^9
We have:
[tex]\mathbf{-a^3b^6}[/tex]
Express b^6 as b^2^3
[tex]\mathbf{-a^3b^6 = -a^3(b^2)^3}[/tex]
Factor out the cubes
[tex]\mathbf{-a^3b^6 = (-ab^2)^3}[/tex]
Similarly;
[tex]\mathbf{-27x^6b^9}[/tex]
Express -27 as -3^3, x^6 as x^2^3 and b^9 as b^3^3
[tex]\mathbf{-27x^6b^9 = (-3)^3(x^2)^3(b^3)^3}[/tex]
Factor out the cubes
[tex]\mathbf{-27x^6b^9 = (-3x^2b^3)^3}[/tex]
Hence, –a^3b^6 and –27x^6b^9 as cubes are: [tex]\mathbf{ (-ab^2)^3}[/tex] and [tex]\mathbf{(-3x^2b^3)^3}[/tex]
(c) Side length of a cube
The volume is given as:
[tex]\mathbf{Volume=\frac15b^3}[/tex]
Take cube roots of both sides
[tex]\mathbf{\sqrt[3]{Volume}= \sqrt[3]{\frac15b^3}}}[/tex]
This gives
[tex]\mathbf{\sqrt[3]{Volume}= b\sqrt[3]{\frac15}}}[/tex]
So, we have:
[tex]\mathbf{Length= b\sqrt[3]{\frac15}}}[/tex]
Hence, the length of the cube is [tex]\mathbf{b\sqrt[3]{\frac15}}}[/tex]
Read more about monomials at:
https://brainly.com/question/11363511