Question

PLEASE HELP!

A cliff jumper jumps out horizontally from a cliff. The cliff is 14 meters tall and she lands in the water 1.5 meters away from the base after falling for 1.7 seconds. With what speed did she jump from the cliff

Answer 1

Answer: v = 0.9 m/s

Explanation:

Due to the horizontal jump, the initial velocity at y-component (Vy) is 0 m/s.

The initial velocity at x-component (Vx) is a constant velocity in the distance 1.5 meters during 1.7 second.

Therefore,

Vx = 1.5 / 1.7 = 0.9 m/s

Vy = 0 m/s