Hi there!
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I believe your answer is:
[tex]\frac{169}{49}[/tex]
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Here’s why:
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[tex](\frac{13}{7})^2\\\rule{150}{0.5}\\\rightarrow \text{Recall the exponent rule: } (\frac{a}{b})^c =\frac{a^c}{b^c}\\\\\rightarrow (\frac{13}{7})^2\\\\\rightarrow \frac{13^2}{7^2}\\\\\rightarrow \boxed{\frac{169}{49} }[/tex]
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Hope this helps you. I apologize if it’s incorrect.
