Question

There are 15 pieces of the same size candy in a bag. Four are banana flavored, three strawberry flavored, six cherry flavored, and two orange flavored. What would be the probability of picking an orange or a cherry flavored candy from the bag? Round to the nearest tenth.

Answer 1

The probability of picking an orange or a cherry flavored candy from the bag is $\frac{8}{15}$.

Given that, total number of candies=15, banana flavoured candies=4, strawberry flavoured candies=3, cherry flavoured candies=6 and orange flavoured candies=2.

We need to find out what would be the probability of picking an orange or a cherry-flavoured candy from the bag.

What is a probability formula?

According to the probability formula, the likelihood that an event will occur is equal to the proportion of favourable outcomes to all outcomes.

The probability of an event$=\frac{Number of favourable outcomes}{Total Number of outcomes}$.

Now, the probability of picking an orange flavored candy from the bag $=\frac{2}{15}$

The probability of picking a cherry flavored candy from the bag $=\frac{6}{15}$

The probability of picking an orange or a cherry flavored candy from the bag $=\frac{2}{15}+\frac{6}{15}=\frac{8}{15}$.

Therefore, the probability of picking an orange or a cherry flavored candy from the bag is $\frac{8}{15}$.

To learn more about the probability visit:

https://brainly.com/question/11034287.

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